The set of points on the Argand plane which s | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The condition $|z| \leq 4$ represents the set of all points inside or on the boundary of a circle centered at the origin with radius $4$.The condi

Vedclass · Accepted Answer

$A$ radius of the circle

Vedclass · Answer

(B) The condition $|z| \leq 4$ represents the set of all points inside or on the boundary of a circle centered at the origin with radius $4$.The condition $\operatorname{Arg}(z) = \frac{\pi}{3}$ represents a ray starting from the origin (excluding the origin itself) making an angle of $\frac{\pi}{3}$ with the positive real axis.The intersection of these two sets is the portion of the ray that lies within the circle,which is a line segment starting from the origin and extending to the boundary of the circle at a distance of $4$ units. This is a radius of the circle.

The set of points on the Argand plane which satisfy both $|z| \leq 4$ and $\operatorname{Arg}(z) = \frac{\pi}{3}$ represents:

Similar Questions

The locus of the point $z$ satisfying $arg\left( \frac{z - 1}{z + 1} \right) = k$ (where $k$ is non-zero) is

$POQ$ is a straight line through the origin $O$. $P$ and $Q$ represent the complex numbers $z_1 = a + ib$ and $z_2 = c + id$ respectively. If $OP = OQ$,then:

The equation $\text{Re}(z^2) = 1$ represents which of the following?

The set of all $\alpha \in R$,for which $w = \frac{1 + (1 - 8\alpha)z}{1 - z}$ is a purely imaginary number,for all $z \in C$ satisfying $|z| = 1$ and $\text{Re}(z) \neq 1$,is

If $z=x+iy$ is a complex number satisfying $\left|z+\frac{i}{2}\right|^2=\left|z-\frac{i}{2}\right|^2$,then the locus of $z$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module